Find the zeroes of p(x) and verify the relationship between the zeroes and coefficients .
p(x) = 6x^2 - 3
NO SPAM PLEASE
Answers
Answered by
1
Step-by-step explanation:
P(X) = 6X²-3
so for zeroes 6X²-3=0
3(2X²-1)=0
=> 2X²-1=0
=>2X²=1
=>X²=1/2
=>X=plus minus 1/√2
so the zeroes are 1/√2 and -1/√2
so for verification we have to find the sum and product of zeroes viz.
1/√2-1/√2. =0. = 0/6. = -b/a
hence verified ✓
also 1/√2×(-1/√2)
=>-1/2
=-3/6=c/a
hence verified ✓
vanshgenius2004:
Well , I have a doubt. ...... When you equated 3(2x^2 - 1 ) = 0 ... so as to find zero of p(x) the at the next step why 3 is not there
because 3 can't be equal to 0
so we will transfer
the three to right hand side
so 0/3 will be there
which is equal to 0
ok...thanks
my pleasure
:D
:D
Answered by
0
thanku friend for your help ♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️
Similar questions