find the zeroes of p(x)
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refer the attachment.
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HELLO FRIEND,
x^2-2x-3
x^2-3x+x-3
x(x-3)+1(x-3)
(x+1) (x-3)
Therefore, x= -1 and 3
x^2-2x-3
x^2-3x+x-3
x(x-3)+1(x-3)
(x+1) (x-3)
Therefore, x= -1 and 3
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