find the zeroes of p(x)=(x-1)³(2x+5)
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The answer is given below :
The given function or polynomial is
p(x)=(x-1)³ (2x+5)
= (x-1) (x-1) (x-1) (2x+5)
ZEROS OF A POLYNOMIAL :
The value of x for which the given polynomial will be valuing zero (0) is called the zero of the polynomial.
In this case, to find the zeroes, we must have
p(x) = 0
⇒ (x-1) (x-1) (x-1) (2x+5) = 0
So, we have
x - 1 = 0
⇒ x = 1
and
2x + 5 = 0
⇒ 2x = -5
⇒ x = -5/2
Therefore, the zeroes of the given polynomial are
x = 1, 1, 1, -5/2
Thank you for your question.
The given function or polynomial is
p(x)=(x-1)³ (2x+5)
= (x-1) (x-1) (x-1) (2x+5)
ZEROS OF A POLYNOMIAL :
The value of x for which the given polynomial will be valuing zero (0) is called the zero of the polynomial.
In this case, to find the zeroes, we must have
p(x) = 0
⇒ (x-1) (x-1) (x-1) (2x+5) = 0
So, we have
x - 1 = 0
⇒ x = 1
and
2x + 5 = 0
⇒ 2x = -5
⇒ x = -5/2
Therefore, the zeroes of the given polynomial are
x = 1, 1, 1, -5/2
Thank you for your question.
VishalSingh1357:
thanks you veryyy much sir
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