Question

find the zeroes of p(y)=y^2-3y-10​

Answer 1

There is only one zero in 10

Answer 2

Answer:

y^2-3y-10

y^2-5y+2y-10

y(y-5)+2(y-5)

we get, (y-5) and (y+2)

first zero :

y-5=0

y=5

first zero is 5 ☑

second zero :

y+2=0

y= (-2)

second zero is -2 ☑

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