Question

Find the zeroes of polynomal p(x) = 6x2 -3-7x

Answer 1

6x2-3-7x=0

6x2-7x-3=0

6x2-9x+2x-3=0

3x(2x-3) +1(2x-3)=0

(3x+1)(2x-3) =0

3x+1=0 or 2x-3=0

3x=-1 or 2x=3

X=-1/3 or x=3/2