Question

find the zeroes of polynomial 2s2 -(1+2root2)s+root 2

Answer 1

$\: \: \: \: 2 {s}^{2} - (1 + 2 \sqrt{2})s + \sqrt{2} \\ = 2 {s}^{2} - 2 \sqrt{2}s - s + \sqrt{2} \\ = 2s(s - \sqrt{2}) - 1(s - \sqrt{2} ) \\ = (s - \sqrt{2} )(2s - 1)$
Therefore,
Zeroes of p(x) are:-
$\sqrt{2} \: and \: ( \frac{1}{2}).$



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