Find the zeroes of polynomial
2x^2-8
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Answer:-
f(x)= 2x^2-8
F(1)= 2(1)^2-8
F(1)=2-8
F(1)=6
F(2)=2(2)^2-8
F(2)=8-8
F(2)=0
2 is zero of polynomial
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