Question

find the zeroes of polynomial..

Answer 1

here is your solution,hope it will help you

Answer 2

Answer:

⇒ x = c/b ______________(i)

⇒ x = -b/a _____________(ii)

Step-by-step explanation:

Given polynomial:

• p(x) = abx² + ( b² - ac ) x - bc

Now,

⇒ abx² + b²x - acx - bc = 0

⇒ bx ( ax + b ) - c ( ax + b ) = 0

⇒ ( bx - c ) ( ax + b ) = 0

Here,

( bx - c )____________(i)

( ax + b )___________(ii)

Finding zeroes of the given polynomial (i) & (ii) :

⇒ bx - c = 0

⇒ bx = c

⇒ x = c/b ______________(i)

⇒ ax + b = 0

⇒ ax = - b

⇒ x = -b/a _____________(ii)