find the zeroes of polynomial 3x^2+x-2
Answers
Answered by
2
Answer:
-1/3, 2
Step-by-step explanation:
3x^2-x-2
3x^2-6x+x-2 =0
3x(x-2) 1(x-2) =0
(3x+1) =0 ( x-2)=0
X= -1/3, 2
Answered by
2
Answer:
Step-by-step explanation:
3x^2-x-2
3x^2-6x+x-2=0
3x(x-2)1(x-2)=0
(3x+1)=0(x-2)=0
x=1/3,2
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