Question

find the zeroes of polynomial (3x²+5x+2) Divide (3x⁴+2x³+x²+5) by (x²+3)and find quatents and remainder class 10 ​

Answer 1

Step-by-step explanation:

Given:-

(3x²+5x+2)

To find:-

zeros of the polynomial

Solution:-

${3x}^{2} + 5x + 2 = 0 \\ = > {3x}^{2} + 3x + 2x + 2 = 0 \\ = > 3x(x + 1) + 2(x + 1) = 0 \\ = > (x + 1)(3x + 2) = 0 \\ = > (x + 1) = 0 \: \: or \: \: (3x + 2) = 0 \\ = > x = ( - 1) \: \: or \: \: x = \frac{ - 2}{3}$

Hence the zeros of polynomial (3x²+5x+2) are -1 or $\frac{-2}{3}$