Find the zeroes of polynomial 4u ^2+ 8u and verify the relationship between the zeroes and its coefficients
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Answer:
we need to equate 4u^2+8u=0
Step-by-step explanation:
so
4u(u+2)=0
4u=0, u+2=0
u=0,-2
sum of roots= - b/a=
-2+0= - (8/4)
-2= - 2
product of roots = c/a
-2*0= 0/4
0=0
hence relation is verified
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