Question

find the zeroes of polynomial 4x^2-7​

Answer 1

X=√7/2 ,√7/2

Step-by-step explanation:

4x^2=7

x^2=7/4

X=√7/2 ,√7/2

Answer 2

Step-by-step explanation:

THE ZEROES OF 4x^2-7Are -+√7/2.

the sum of zeroes is -√7/2 +√7/2=0

=-b/a

product of zeroes is (-√7/2)(√7/2)

=-7/4

=-c/a

hope it's helps........