Question

Find the zeroes of polynomial 6×^2-3-7×

Answer 1

Given:-

๛p(x)=6x²-7x-3

$\rule{200}{1}$

To Find:-

✪The Zeros of the Polynomial→p(x)?

$\rule{200}{1}$

AnsWer:-

☞x=$\frac{-1}{3}$ and $\frac{3}{2}$

$\rule{200}{1}$

↝6x²-7x-3=0

➜S=-7

➜P=-18

▼-9+2=-7→S

▼-9×2=-18→P

↝6x²-9x+2x-3=0

↝3x(2x-3)+1(2x-3)=0

↝3x+1=0

↝3x=-1

↝x=-⅓

↝2x-3=0

↝2x=3

↝x=$\frac{3}{2}$

$\rule{200}{2}$

Answer 2

$\huge\purple{\textbf{\underline{\underline{Fair Content}}}}$

=6x²-7x-3

=6x²+2x-9x-3

=2x(3x+1)-3(3x+1)

=(2x-3)(3x+1)

⇒2x-3=0                                    or                            ⇒3x+1=0

⇒x=3/2                                       or                           ⇒ x= - 1/3

α=3/2 ,β= - 1/3

⇒α+β= -b/a

⇒3/2+(-1/3)= - (-3)/6

⇒3/2-1/3=1/2

⇒7/6 =1/2

 ⇒αβ=c/a

 ⇒ 3/2(-1/3)= -7/6

⇒-1/2= -7/6

 ⇒1/2=7/6