Math, asked by predator00737, 4 months ago

find the zeroes of polynomial 6x^2+29x+35​

Answers

Answered by preritagrawal08
4

Answer:

x = -7/3  or x = -5/2

Step-by-step explanation:

6x²+29x+35 = 0

6x²+15x+14x+35 = 0

3x(2x+5)+7(2x+5) = 0

(3x+7)(2x+5)

x = -7/3  or x = -5/2

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Answered by ericaeveespaldon028
2

x = -7/3  or x = -5/2

6x²+29x+35 = 0

6x²+15x+14x+35 = 0

3x(2x+5)+7(2x+5) = 0

(3x+7)(2x+5)

x = -7/3  or x = -5/2

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