find the zeroes of polynomial 6x^2+29x+35
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Answered by
4
Answer:
x = -7/3 or x = -5/2
Step-by-step explanation:
6x²+29x+35 = 0
6x²+15x+14x+35 = 0
3x(2x+5)+7(2x+5) = 0
(3x+7)(2x+5)
x = -7/3 or x = -5/2
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Answered by
2
x = -7/3 or x = -5/2
6x²+29x+35 = 0
6x²+15x+14x+35 = 0
3x(2x+5)+7(2x+5) = 0
(3x+7)(2x+5)
x = -7/3 or x = -5/2
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