Question

find the zeroes of polynomial is P(x)=X2-3​

Answer 1

x^2-3

(x)^2-(√3)^2

(x-√3)(x+√3)

x=√3 or x= -√3.

Answer 2

HEY ❤️ ❤️ ❤️ ❤️


$p(x ) = {x}^{2} - 3 \\ \\ = {x}^{2} - 3 = 0 \\ \\ = {x}^{2} = 3 \\ \\ = x = \sqrt{3}$



$\sqrt{3} = 1.732(approx)$



$therefore \: \: \sqrt {3} \: \: \: \: is \: the \\ zero \: of \: the \: polynomial$



HOPE IT HELPS ❤️