Question

find the zeroes of polynomial p(t)=tsquare+2t+1​

Answer 1

Answer:

t3 – 2t2 – 15t Taking t common, we get, t ( t2 -2t -15) Splitting the middle term of the equation t2 -2t -15, we get, t( t2 -5t + 3t -15) Taking the common factors out, we get, t (t (t-5) +3(t-5) On grouping, we get, t (t+3)(t-5) So, the zeroes are, t=0 t+3=0 ⇒ t= -3 t -5=0 ⇒ t=5 Therefore, zeroes are 0, 5 and -3 Verification: Sum of the zeroes = – (coefficient of x2) ÷ coefficient of x3 α + β + γ = – b/a (0) + (- 3) + (5) = – (- 2)/1 = 2 = 2 Sum of the products of two zeroes at a time = coefficient of x ÷ coefficient of x3 αβ + βγ + αγ = c/a (0)(- 3) + (- 3) (5) + (0) (5) = – 15/1 = – 15 = – 15 Product of all the zeroes = – (constant term) ÷ coefficient of x3 αβγ = – d/a (0)(- 3)(5) = 0 0 = 0Read more on Sarthaks.com - https://www.sarthaks.com/878318/find-zeroes-polynomial-verify-relation-between-the-coefficients-zeroes-the-polynomial

Answer 2

Step-by-step explanation:

ur answer iss in attachment