Question

find the zeroes of polynomial

p(x)=2x^3-5x^2-14x+8

Answer 1

Answer:

2x³ - 5x² - 14x + 8 = 0

put x = -2 we get 0 hence x = -2 is a root of the given equation 

2x²(x+2) -9x(x+2) +4(x+2) = 0

(x + 2)(2x² -9x +4) = 0

(x + 2)(2x² -8x - x + 4) = 0

(x + 2){2x(x-4) -1(x-4)} = 0

(x+2)(x-4)(2x-1) = 0

x = -2, 4, 1/2

Answer 2

Answer:

Concept:

A polynomial is an expression. An expression is a mathematical statement without an equals sign (=).

Find:

find the zeroes of polynomial

Given:

find the zeroes of polynomial

p(x)=2x³-5x²-14x+8

Step-by-step explanation:

Polynomials are algebraic expressions that contain uncertainties and constants. You can think of polynomials as a dialect of mathematics.

p(x)=2x³-5x²-14x+8

2x³-5x²-14x+8 = 0

put x=-2 we get O

hence x = -2 is a root of the given equation

(x+2)(2x² -9x +4)= 0

2x²(x+2)-9x(x+2)+4(x+2) = 0

(x+2)(2x² -8x-x+4)= 0

(x+2){2x(x-4) -1(x-4)} = 0

(x+2)(x-4)(2x-1)=0

x= -2,4,1/2

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