Question

find the zeroes of polynomial

p(x)=2x^3-5x^2-14x+8
Apart from the solution attached above, if you have any other method then only please send..everyone is attaching this solution and this is hard for me..so any easy method?​

Answer 1

Answer:

Step-by-step explanation:

We have polynomial p ( x ) = 2x3 - 5x2 - 14x + 8

We know relationship between zeros and coefficient of cubic polynomial is As:

Sum of Zeros = − Coefficient of x2Coefficient of x3- Coefficient of x2Coefficient of x3

And

Product of Zeros = − Constant termCoefficient of x3- Constant termCoefficient of x3

So,

Sum of Zeros = −−52--52   = 5252

And

Product of Zeros = −82-82  = - 4