Find the zeroes of polynomial p(x) = 6x+6x-3-7x
Answers
Answered by
3
P(x) = 6x+6x-3-7x
P(0)= 6*0+6*0-3-7*0
= 0+0-3-0
= - 3 Ans
P(0)= 6*0+6*0-3-7*0
= 0+0-3-0
= - 3 Ans
Answered by
3
Given,
6x²-7x - 3
to find the zeroes of the polynomial,
6x²-7x - 3 = 0
6x²-9x +2x -3 = 0
3x(2x-3) + 1(2x -3) = 0
(3x+1) (2x-3) = 0
x = -1/3 or 3/2
sum of the zeroes = 3/2 - 1/3 = 7/6 = - ( co-efficient of x) / co-efficient of x²
product of the zeroes = -1/3 × 3/2 = -1/2 = constant / co-efficient of x²
6x²-7x - 3
to find the zeroes of the polynomial,
6x²-7x - 3 = 0
6x²-9x +2x -3 = 0
3x(2x-3) + 1(2x -3) = 0
(3x+1) (2x-3) = 0
x = -1/3 or 3/2
sum of the zeroes = 3/2 - 1/3 = 7/6 = - ( co-efficient of x) / co-efficient of x²
product of the zeroes = -1/3 × 3/2 = -1/2 = constant / co-efficient of x²
Similar questions