Question

Find the zeroes of polynomial p(x) =x^2-4√3​

Answer 1

Step-by-step explanation:

P ( x ) = x² - 4

We can also write this as :

⇒ P ( x ) = (x)² - (2)²

Identity : a² - b² = (a + b)(a - b)

⇒ P ( x ) = (x + 2)(x - 2)

To find the zeroes, P ( x ) = 0

•°• 0 = (x + 2)(x - 2)

Using Zero Product Rule

⇒ (x + 2) = 0 and (x - 2) = 0

⇒ x = - 2 and x = 2

Hence, the zeroes are 2 and - 2.