Question

Find the zeroes of polynomial p(x)=x(x+1)(x+2)

Answer 1

The zeroes are:-
x=0
x=-1
x=-2
Hope this will help you

Answer 2

GIVEN :-

P(x) = x(x+1)(x+2)

(x+1) = 0
=> x = (-1)

(x+2) = 0
=> x = (-2)

.
We can take P(0),
P(0) = 0*(0+1)(0+2)
P(0) = 0*1*2
P(0) = 0

Now,
taking P(-1),
P(-1) = (-1)*(-1+1)(-1+2)
P(-1) = (-1)*0*1
P(-1) = 0

Now,
taking P(-2),
P(-2) = (-2)*(-2+1)(-2+2)
P(-2) = (-2)*(-1)*0
P(-2) = 0

Hence,
0, (-1) and (-2) are the zeroes of the polynomial P(x) = x(x+1)(x+2)