Question

Find the zeroes of polynomial p(x) = x²-16​

Answer 1

Answer:

Step-by-step explanation:

Given -

p(x) = x² - 16

To Find -

Zeroes of the polynomial

Now,

→ x² - 16

→ (x)² - (4)²

Using the identity of a² - b² = (a + b)(a - b)

→ (x + 4)(x - 4)

Zeroes are -

→ x + 4 = 0 and x - 4 = 0

→ x = -4 and x = 4

Verification :-

α + β = -b/a

→ -4 + 4 = -(0)/1

→ 0 = 0

LHS = RHS

And

αβ = c/a

→ -4 × 4 = -16/1

→ -16 = -16

LHS = RHS

Hence,

Verified...

It shows that our answer is absolutely correct.

Answer 2

Answer:

x x x =16

x=√16=4

Step-by-step explanation:

the zeros is 4