Question

Find the zeroes of polynomial p(x) = x2-27. answer​

Answer 1

Answer:

P(x)=x²-27

Now p(x)=0

=> x²-27=0

=> x²=27

=> x=±√27

=+3√3&-3√3

So the zeroes are+3√3 and -3√3.

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Answer 2

Answer:

p(x)=x^2-27=0

x^2=27

x=root27

x=+or-root3root3