find the zeroes of polynomial px root 2 x² -3x -2 root 2
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Answer:
√2x²-3x-2√2
√2x²-4x+x-2√2
√2x(x-2√2)+1(x-2√2)
(x-2√2)(√2x+1)
(x-2√2)=0. (√2x+1)=0
x=2√2. x=-1/√2
therefore the zeros are. 2√2,-1/√2
hope this will help you...
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