find the zeroes of polynomial px=x^2+6x+9 and verify the rellation between zeroes and cofficient
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Answer:
zeroes are real and equal
Step-by-step explanation:
Given:-
p(x)=x²+6x+9
solution:-
put p(x)=0
x²+6x+9=0
x=[-6+-√(0)]/2
x=-3,-3
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