Question

find the zeroes of polynomial x^2-2x-8 and verify the relationship between the zeroes and its coefficients

Answer 1

$Heya$‼

$Given\:polynomial:x^2-2x-8$

$x^2-2x-8=0$

$x^2-4x+2x-8=0$

$x(x-4)+2(x-4)=0$

$(x+2)(x-4)=0$

$(x+2)=0\:or\:(x-4)=0$

$x=-2\:or\:x=4$

Let @ and ß are the zeroes of given polynomial.



$Sum\:of\:zeroes=\frac{-coefficient\:of\:x}{coefficient\:of\:x^2}$

OR

$=$@ + ß

$=>- \frac{-2}{1}$
OR
$=> -2 + 4$

$=> -2$




$Product\:of\:zeroes=\frac{constant\:term}{coefficient\:of\:x^2}$

OR

$=$@ $*$ ß

$=> \frac{-8}{1}$
OR
$=> -2 * 4$

$=> -8$

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