Math, asked by vijeta23, 10 months ago

find the zeroes of polynomial x^2+(3/2√5) x-1/2​

Answers

Answered by Vishal101100
5

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Answered by iram86
1

Answer:

x^2+3/2√5x-5

Relationship between zeroes and coefficients

Sum of zeroes=-(coefficient of x)/coefficient of x^2=-3/2√5/1=-3/2√5

Product of zeroes=constant term/coefficient of x^2=-5/1=-5

Step-by-step explanation:

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