find the zeroes of polynomial x^2+(3/2√5) x-1/2
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Answer:
x^2+3/2√5x-5
Relationship between zeroes and coefficients
Sum of zeroes=-(coefficient of x)/coefficient of x^2=-3/2√5/1=-3/2√5
Product of zeroes=constant term/coefficient of x^2=-5/1=-5
Step-by-step explanation:
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