Question

find the zeroes of polynomial x^2+7x-8, and verify the relationship between the zeroes and the coefficients

Answer 1

sorry...here is your answe have,
p(x) = x² + 7x - 8
And we have to find zeroes of the given polynomial. So , lets do it !!!!
=> Given : 
=> x² + 7x - 8
=> x² + 8x - x - 8 
=> x(x + 8 ) - 1( x + 8 ) 
=> ( x + 8 ) ( x - 1) are the factors of the given polynomial .
If x + 8 = 0 
∴ x = -8 is the zero of the polynomial 
If x - 1 = 0 
∴ x = 1 is the zero of the polynomial 
Therefore, -8 and 1 are the zeroes of the given polynomial .
Now, relation between the zeroes and the coefficient.
Let, α = -8 and β = 1
We know that,
α + β = -b/a
-8 + 1 = -7/1 = -b/a
Also,
αβ = c/a
-8* 1 = -8/1 = c/a 
Therefore, relation between the zeroes and the coefficient is verified