find the zeroes of polynomial x^3-7x+6
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Answer:
(x-6)(x-1)(x+1)(x-1)
Step-by-step explanation:
x^3-7x+6
can be written as
x^3-1x-6x+6
x(x^2-1)-6(x-1)
(x-6)(x^2-1)(x-1) ;x^2-1^2=(x+1)(x-1)
(x-6)(x+1)(x-1)(x-1)
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