Math, asked by prashant2153, 11 months ago

find the zeroes of polynomial x^3-7x+6

Answers

Answered by sagarasagar49
3

Answer:

(x-6)(x-1)(x+1)(x-1)

Step-by-step explanation:

x^3-7x+6

can be written as

x^3-1x-6x+6

x(x^2-1)-6(x-1)

(x-6)(x^2-1)(x-1) ;x^2-1^2=(x+1)(x-1)

(x-6)(x+1)(x-1)(x-1)

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