Question

find the zeroes of polynomial x²+1/6x_2 and verify the relationship between zeroes and coefficients ​

Answer 1

Step-by-step explanation:

x²+1/6x-2

only 1/6 has denominator take all numbers in that denominator

(6x²+x-12)/6=0

6x²+x-12=0

take 2 numbers whose sum is 1 and product 12×6=72

these are-8,9

6x²+9x-8x-12

3x(2x+3)-4(2x+3)

(2x+3)(3x-4)=0

2x+3=0

3x-4=0

solving both equations

x=-3/2 & 4/3

hope you got it

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