Question

find the zeroes of polynomial x²-49

Answer 1

hello frnd here's the answer to the given question

x^2-49=0
(x-7)(x+7)
therefore x = +7 and -7

Answer 2

$\boxed{\boxed{\large\mathbf{7, -7}}}$
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$\underline{\underline{\huge\mathfrak{ANSWER}}}$

$\mathbf{x^2 - 49}$

$\mathsf{\Longrightarrow (x)^2 - (7)^2}$

$\underline\text{Using the identity,}$

$\boxed{\mathbf{a^2 - b^2 = (a + b)(a - b)}}$

$\mathsf{\Longrightarrow (x + 7)(x - 7)}$

Hence, the zeroes are :

x + 7 = 0
$\mathsf{\Longrightarrow \bf\boxed{x = -7}}$

x - 7 = 0
$\mathsf{\Longrightarrow \bf\boxed{x = 7}}$

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