Find the zeroes of polynomials b) t2-2x-8
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Answered by
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t²-2t-8
=(t-4)(t+2)
=4 ,-2
......
Answered by
1
Answer:
Here it is.............. (In place of 't' it is 'x')
>> x^2-4x+2x-8= x(x-4) +2(x-4) = (x+2) (x-4) = -2, 4
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