Question

Find the zeroes of polyonimal x2-x-12 by graph

Answer 1

x2-x-12
x2-4x+3x-12
x(x-4)+3(x-4)
(x+3)(x-4)
x+3=0,x-4=0
x=-3,x=4

Answer 2

x²-x-12

x²-4x+3x-12

x(x-4) +3(x-4)

(x-4) (x+3)

Zeroes are....

x-4=0

x=0+4

x=4


x+3=0

x=0-3..

x= - 3

ZEROES ARE..... 4,-3