Question

Find the zeroes of q(y)=7y²-11/3y-2/3 by spliting the middle term?

Answer 1

$Heya$‼

7y² – 11y/3 – 2/3 = 0

Multiplying by 3 on both sides,

21y² – 11y – 2 = 0

21y² – 7y + 6y – 2 = 0

7y ( 3y – 1 ) + 2 ( 3y – 1 ) = 0

( 7y + 2 ) ( 3y – 1 ) = 0

( 7y + 2 ) = 0 or ( 3y – 1 ) = 0

y = –2/7 or y = 1/3