Question

find the zeroes of quadratic equation 2x^2-9​

Answer 1

$2x {}^{2} - 9 = 0 \\ {2x}^{2} = 9 \\ {x}^{2} = \frac{9}{2} \\ x = \frac{ \sqrt{9} }{ \sqrt{2} } = \frac{ 3}{ \sqrt{2} }$

Answer 2

Answer:

zeros of the quadratic equation are

x = 3/√2 or x =- 3/√2

Step-by-step explanation:

given quadratic equation is,

2x^2 - 9

equate the equation with zero then the equation will be,

2x^2 - 9 = 0

↪( √2 x) ^2 - (3)^2 = 0

we know the standard algebraic identity formula

(a^2 - b ^2) = ( a + b) ( a - b)

therefor from above formula we can get,

( √2 x) ^2 - (3)^2 = 0

( √2x - 3 ) ( √2x + 3)

x = 3 / √2 x = - 3 /√2

so the values of x are

[x = 3/√2]

or

[x = - 3/√2]

here we used factorization method to find the roots of the quadratic equation, in this method we have to split the middle term and get a factors then we can find the zeroes of the quadratic equation.