Question

Find the zeroes of quadratic equation x^2-2x-8

Answer 1

$\sf{x^2-2x-8=0}\\\\\sf{\longrightarrow x^2-4x+2x-8=0}\\\\\sf{\longrightarrow x(x-4)+2(x-4)=0}\\\\\sf{\longrightarrow (x-4)(x+2)=0}\\\\\sf{\longrightarrow (x-4)=0\:\:or\:\:(x+2)=0}\\\\\sf{\longrightarrow x=4\:\:or\:\:x=-2}$

Answer 2

Answer:

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