Question

find the zeroes of quadratic equations 1)x2-x-8 in detail​

Answer 1

Answer:

${x}^{2} - x - 8 = 0$

${x}^{2} + 4x - 4x - 8 = 0$

$2x( x + 2) - 4(x + 2) = 0$

$(2x - 4) \: \: \: (x + 2) = 0$

$(2x - 4) = 0 \\ 2x = 4 \\ x = \frac{4}{2} \\ x = 2$

$x + 2 = 0 \\ x = - 2$

So quadratic equation is solved.

x = 2, -2

Step-by-step explanation:

Hope its help you