find the zeroes of quadratic equatn above
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Heya!!
Good eve & here's your answer:
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Given quadratic equation = √3x² - 8x + 4√3 = 0
We should factorize the equation first.
=√3x²-6x-2x+4√3 = 0
= √3x(x-2√3)-2(x-2√3) = 0
= (√3x-2) (x-2√3) = 0
= (√3x-2) = 0 , (x-2√3) = 0
= x = 2/√3 , x = 2√3.
____________________________________________________________________✨
HOPE THIS CLEARED YOUR DOUBT ☺
#BE BRAINLY
Good eve & here's your answer:
____________________________________________________________________✨
Given quadratic equation = √3x² - 8x + 4√3 = 0
We should factorize the equation first.
=√3x²-6x-2x+4√3 = 0
= √3x(x-2√3)-2(x-2√3) = 0
= (√3x-2) (x-2√3) = 0
= (√3x-2) = 0 , (x-2√3) = 0
= x = 2/√3 , x = 2√3.
____________________________________________________________________✨
HOPE THIS CLEARED YOUR DOUBT ☺
#BE BRAINLY
meez94:
tq
your welcome
Pleasure!
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ok
Answered by
3
√3x²-8x+4√3=0
√3x²-6x-2x+4√3=0
therefore,
√3x(x-2√3)-2(x-2√3)=0
therefore,
(√3x-2)(x-2√3)=0
therefore, the zeros of the equation are 2/√3 and 2√3.
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