Question

Find the zeroes of quadratic polynomial 2x 2-25

Answer 1

$2{x}^{2} - 25 \\ (\sqrt{2} x + 5)( \sqrt{2} x - 5) \\ x = - 5 \div \sqrt{2} \: and \: 5 \div \sqrt{2}$
hope this helps you

Answer 2

2x^2-25=0

2x^2=25

x^2=25/2

X=+- 5√2÷✓2