Question

Find the zeroes of quadratic polynomial 4u square + 8u??

Answer 1

Answer:

0,-2

Step-by-step explanation:

4u^2+8u

=4u(u+2)

there, u+2=0

u= -2

check: p(u)=4u^2+8u

p(-2)=4( -2)^2+8(-2)

=16+(-16)

=0