Question

Find the zeroes of quadratic polynomial (5u²+10u) verify the relation between zeros and coefficient

Answer 1

I hope u understood!!

Answer 2

$Given \: Quadratic \: polynomial \: 5u^{2}+10u$

$5u^{2} + 10u = 5u(u+2)$

$5u^{2}+10u \:is \:zero \: when \: 5u = 0 \:Or \\u + 2 = 0 , i.e., \: when \: u = 0 \: Or \: u = -2$

$So, \: the \: Zeroes \: of \: 5u^{2}+10u \:are \\0 \: and \: -2$

$Here, the \: coefficient \:of \: u^{2} = 5, \\coefficient \: of \:u = 10 \:and \: constant = 0$

Verification:

$Sum \:of \:the \: zeroes \\= 0 -2 \\= \frac{-2}{1} \\= \frac{-(coefficient \:of \: u)}{coefficient \:of \:u^{2}}$

$Product \:of \:the \: zeroes \\= 0 \times (-2) \\= \frac{0}{1} \\= \frac{constant}{coefficient \:of \:u^{2}}$

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