find the zeroes of quadratic polynomial 7y2-11/3y-2/3 and find the relationship between zeroes and coifficents
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Step-by-step explanation:
7y2-11/3y-2/3
1/3(21y2-11y-2)
1/3(21y2-14y+3y-2)
1/3(7y(3y-2)+(3y+2)
1/3 (3y-2)(7y+1)
y=2/3
y=-1/7
Alpha + Beta = 11/21 = coefficient of y/ coefficient of of y2
Alpha × Beta= -2/21=constant term / coefficient of y2
Hope it helps!!
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