Math, asked by frinsonpinchu, 3 months ago

find the zeroes of quadratic polynomial 7y2-11/3y-2/3 and find the relationship between zeroes and coifficents

Answers

Answered by Preetha2006
3

Step-by-step explanation:

7y2-11/3y-2/3

1/3(21y2-11y-2)

1/3(21y2-14y+3y-2)

1/3(7y(3y-2)+(3y+2)

1/3 (3y-2)(7y+1)

y=2/3

y=-1/7

Alpha + Beta = 11/21 = coefficient of y/ coefficient of of y2

Alpha × Beta= -2/21=constant term / coefficient of y2

Hope it helps!!

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