Question

Find The Zeroes Of quadratic polynomial f(x)= X2 +2x +1 and find the relation between zeroes and cofficients​

Answer 1

Step-by-step explanation:

x2+(1+1)x+1=0

x2+x+x+1=0

x(x+1)+1(x+1)

(x+1)(x+1)

x=-1,-1

Relationship

-1-1=-(coeffienct.of x)/coeffiecient of x2

-2=-(-2)/1

lhs=rhs

-1×-1=constant term/coefficient of x2

1=1/1

lhs=rhs