Question

Find the zeroes of quadratic polynomial h(t)=t^2-15

Answer 1

Step-by-step explanation:

on factorising t^2-15 we get

$(t - \sqrt[2]{15} )(t + \sqrt[2]{15} )$

so zeroes r

$\sqrt[2]{15} \: and \:( - \sqrt[2]{15} )$