Question

Find the zeroes of quadratic polynomial h(t)=t^2-15

Answer 1

Answer:

t2 - 15 = (t + √15)( t - √15)

therefore t+ √15 = 0

i.e. t = - √15

similarly t - √15 = 0

and t = √15

so the zeros are √15 and - √15

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Answer 2

$\huge \fbox \red{Solution:}$

Given,

h(t) = t

2 – 15 = t2 +(0)t – 15

To find the zeros, we put h(t) = 0

⇒ t

2 – 15 = 0

⇒ (t + √15)(t - √15)= 0

This gives us 2 zeros, for

t = √15 and t = -√15

Hence, the zeros of the quadratic equation are √15 and -√15.

Now, for verification

Sum of zeros = - coefficient of t / coefficient of t2

√15 + (-√15) = - (0) / 1

0 = 0

Product of roots = constant / coefficient of t2

√15 x (-√15) = -15/1

-15 = -15

Therefore, the relationship between zeros and their coefficients is verified.