Find the zeroes of quadratic polynomial of x2+13x+36=0
Answers
Answered by
5
x²+ 13x+36
=x²+9x+4x+36
=x(x+9)+4(x+9)
=(x+4)(x+9)
=x+4=0 and x+9=0
=x=-4 and x=-9
=x²+9x+4x+36
=x(x+9)+4(x+9)
=(x+4)(x+9)
=x+4=0 and x+9=0
=x=-4 and x=-9
Answered by
2
x²+ 13x+36
=x²+9x+4x+36
=x(x+9)+4(x+9)
=(x+4)(x+9)
=x²+9x+4x+36
=x(x+9)+4(x+9)
=(x+4)(x+9)
Similar questions