Find the zeroes of quadratic polynomial p(x) = _9x^2
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This equation is not quadratic
It should be in form ______----Ax^2+bx+c
Vksingh7:
the answer is x= +1/3 and -1/3
how
9x^2 = 0. »»» x^2 = 1/9 »»»» x = +-(1/9)^1/2. »»» x = +-1/3
you are right
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