find the zeroes of quadratic polynomial x2+0x-15 and verify the relationship between them and coefficient
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I don’t know sorry bro I think so answer is 193792
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Answer:
Answer :
Let f(x) = x2 – 15
Arranging equation in proper form.
Now, f(x) = x2 + 0x – 15
To find out zeros of the given polynomial.
We put f(x) = 0
⇒ x2 – 15 = 0
∴ x2 – = 0
So, (x + )(x – ) = 0
When, (x + ) = 0
Then, x = – .
When. (x – ) = 0
Then, x =
⇒ Our zeros are α = – and β = .
⇒ sum of zeros = α + β = – +
⇒ sum of zeros = α + β = 0
⇒ Product of zeros = αβ = – = – 15
Now, Comparing f(x) = x2 + 0x – 15 with standard equation ax2 + bx + c.
We get, a = 1, b = 0 and c = – 15.
We can verify,
⇒ Sum of zeros =
i.e. α + β =
∴ α + β = 0
⇒ Product of zeros =
αβ =
Step-by-step explanation:
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