Question

find the zeroes of quadratic polynomial x2-3x-10 and verify the relationship between the zeroes and coefficient​

Answer 1

Answer:

x²-3x-10 =0

x²-5x+2x-10 =0

x(x-5) + 2(x-5) =0

(x-5)(x+2) =0

x-5 =0, x+2 =0

x= 5, x= -2

alpha = 5, beta = -2

a = 1, b=3, c= -10

alpha + beta = -b/a

5+(-2) = -(-3)/1

5-2 = 3

3 = 3

verified

alpha x beta = c/a

(5)(-2) = -10/1

-10 = -10

hence verified

Hope it helped, best of luck (☆^ー^☆)

Answer 2

zeroes are 2 and -5

x^-3x -10

x2 -(5+2)x -10

x2 -5x+2x-10

(x-2) (x+5)

x= 2, -5

verification

a=1, b=-3 ,c=-10

sum of zeroes = -b/a

2-5 = -3/1

-3 = -3

product of zeroes =c/a

2*-5 = -10/1

-10 = -10

I hope it will help you

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