find the zeroes of quadratic polynomial x²-81, and verify the relationship between the zeroes and the Coefficients.
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1
Answer:
49x
2
−81
=(7x)
2
−(9)
2
=(7x+9)(7x−9)
x=−
7
9
, x=
7
9
The zeros of the polynomials are −
7
9
,
7
9
Relationship between the zeros and the coefficients of the polynomials-
Sum of the zeros=-
coefficient of x
2
coefficient of x
=−(
49
0
)=0
Also sum of zeros=−
7
9
+
7
9
=
7
−9+9
=0
Product of the zeros =
coefficient of x
2
constant term
=
49
−81
Also the product of the zeros=−
7
9
×
7
9
=
49
−81
Hence verified.
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